| (2) 与式より log|y|=log|(x-1)^2/(x+1)^3| ∴log|y|=2log|x-1|-3log|x+1| 両辺xで微分して y'/y=2/(x-1)-3/(x+1) ∴y'={2/(x-1)-3/(x+1)}y =2(x-1)/(x+1)^3-3{(x-1)^2}/(x+1)^4
(3) 与式より logy=log{√{(x-1)/(x+1)}} ∴logy=(1/2){log|x-1|-log|x+1|} 両辺xで微分して y'/y=(1/2){1/(x-1)-1/(x+1)} ∴y'=(1/2){1/(x-1)-1/(x+1)}y =(1/2){1/(x-1)-1/(x+1)}√{(x-1)/(x+1)}
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