| ■9232 / inTopicNo.2) |
Re[1]: 因数分解
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□投稿者/ だるまにおん 大御所(1199回)-(2006/02/17(Fri) 23:11:03)
 | (x^4)+(x^2)(z^2)-(y^4)-(y^2)(z^2)
=(x^4)-(y^4)+(z^2){(x^2)-(y^2)}
={(x^2)-(y^2)}{(x^2)+(y^2)}+(z^2){(x^2)-(y^2)}
={(x^2)-(y^2)}{(x^2)+(y^2)+(z^2)}
=(x-y)(x+y)(x^2+y^2+z^2)
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