| ■39780 / inTopicNo.2) |
Re[1]: 因数分解の問題
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□投稿者/ WIZ 一般人(32回)-(2009/10/30(Fri) 23:42:23)
 | (1) u = x^2, v = y^2とおけば、
x^4+2x^2y^2-3y^4 = u^2+2uv-3v^2 = (u-v)(u+3v) = (x^2-y^2)(x^2+3y^2) = (x-y)(x+y)(x^2+3y^2)
(2)
4x^3y+29x^2y^2-24xy^3 = xy*(4x^2+29xy-24y^2) = xy*(x+8y)(4x-3)
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