■14421 / inTopicNo.2) |
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□投稿者/ soredeha 一般人(23回)-(2006/07/08(Sat) 06:34:12)
| an/an+1= (logn/n)/ {log(n+1)/(n+1)} ={(n+1)/n}{logn/log(n+1)} (n+1)/n=1+1/n → 1 ( n → ∞ ) logn/log(n+1)=logn/log{n(1+1/n)}=logn/{logn+log(1+1/n)} =1/{1+(1/logn)log(1+1/n)} → 1/{1+0・log1}=1 ( n → ∞ ) したがって an/an+1 → 1・1=1 |x|<1 で収束
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